part of an ancient coin was discovered it was measured to be only an 80° section of it was left. if the coin had a radius of 0.9 inches, what was the area of this sector
Accepted Solution
A:
Area of sector = [tex] \frac{θ}{360} \times \pi {r}^{2} [/tex] [tex] = \frac{80}{360} \times \pi \times {0.9}^{2} [/tex] [tex] = \frac{80}{360} \times \pi \times 0.81[/tex] [tex] = 0.565[/tex] inches Answer has been been rounded off to 3 significant figures.