A rectangle is drawn so that the width is 4 feet shorter than the length. The area of the rectangle is 45 square feet. Find the length of the rectangle.

The length of the rectangle is 9 feetStep-by-step explanation:A rectangle is drawn so that:The width is 4 feet shorter than the lengthThe area of the rectangle is 45 square feetAssume that the length of the rectangle is x feet∵ The length of the rectangle = x feet∵ The width of the rectangle is 4 feet shorter than the length∴ The width of the rectangle = (x - 4) feet∵ The area of the rectangle = length × width∴ The area of the rectangle = x(x - 4)- Simplify it∴ The area of the rectangle = x² - 4x∵ The area of the square = 45 feet²- Equate the two expressions of the area∴ x² - 4x = 45- Subtract 45 from both sides∴ x² - 4x - 45 = 0Use your calculator to find the value of x∴ x = 9 and x = -5- We will reject the value of x = -5 because there is no negative   dimensions∴ x = 9∵ The length of the rectangle = x∴ The length of the rectangle = 9 feetThe length of the rectangle is 9 feetLearn more:You can learn more about area of figures in brainly.com/question/4713715#LearnwithBrainly