Indicate the equation of the given line in standard form. The line containing the longer diagonal of a quadrilateral whose vertices are A (2, 2), B(-2, -2), C(1, -1), and D(6, 4).
Accepted Solution
A:
Answer:3x-4y=2Step-by-step explanation:step 1Plot the figurewe haveA (2, 2), B(-2, -2), C(1, -1), and D(6, 4)using a graphing toolThe longer diagonal is BDsee the attached figurestep 2Find the slope of the diagonal BDwe haveB(-2, -2) and D(6, 4)m=(4+2)/(6+2)m=3/4step 3Find the equation of the diagonal BD into point slope formy-y1=m(x-x1)we havem=3/4D(6,4)substitutey-4=(3/4)(x-6)step 4Convert the equation in standard formThe equation of the line in standard form is equal toAx+By=Cy-4=(3/4)(x-6)y=(3/4)x-(18/4)+4Multiply by 4 both sides4y=3x-18+163x-4y=18-163x-4y=2 -----> equation of the diagonal in standard form